By Jiuping Xu
The publication discusses the characters of tubular strings in HTHP(High Temperature - excessive strain) oil and fuel wells. those characters contain the mechanical habit of tubular strings, the temperature and strain edition of tubular strings in several stipulations. for various stipulations, the e-book establishes mathematical types, and discusses answer life and specialty of a few types, supplies algorithms comparable to the several types. The booklet offers numerical experiments to make sure the validity of types and the feasibility of algorithms, and likewise mentioned the impression of the parameters of versions for oil and gasoline wells.
This ebook is written for researchers and technicians in petroleum and gasoline trying out and creation engineering. it's also meant to function a reference booklet for school academics and students.
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Additional info for Tubular String Characterization in High Temperature High Pressure
K0 ds Thus, d Fe = fe (s), ds where, Fτe is the equivalent axial load under the internal and external pressure equivalent action, Fτ is actual axial load, fτe is the equivalent axial external force, fne is the equivalent external force for the principal normal, fbe is the equivalent external force for the subnormal. qe is the equivalent dead weight after considering the internal and external fluid action on the tubular string, and q is the actual dead weight. , dM = Fe (s) × τ(s). 10), we can get: d Fe dFn dFb dFτe = τ0 + Fτe K0 n0 + n0 + Fn (−K0 τ0 + T0 b0 ) + b 0 − F b T0 n 0 ds ds ds ds dFτe dFn dFb = − K0 Fn τ0 + Fτe K0 + − T 0 Fb n 0 + T 0 F n + b0 .
Distribution external force vector f (s)ds for the tubular string differential element: (1) Tubular string deadweight qk (2) Normal contact pressure of the curved tubular string and well wall N = N (cos θ n0 , −sin θ b0 ) (3) Tubular string internal and external flowing fluid viscous friction force ( fuo + fui )τ0 (4) Axial friction force ff1 = −f1 N τ0 (5) Circumferential hoop friction force ff2 = −f2 N (sin θ n0 + cos θ b0 ) Thus, the whole external force vector can be represented as follows: f (s) = ( fui + fuo − f1 N )τ0 + N cos θ n0 − N sin θ b0 − f2 N (sin θ n0 + cos θ b0 ) + qk, where, f1 represents the axial friction coefficient between the tubular string and well wall; f2 represents the circumferential hoop friction coefficient between the tubular string and well wall; fui , fuo represents the viscous friction coefficient of the external and internal fluid acting on the tubular string.
1 Tubular displacement analysis Assume that the tubular displacement caused by the axial force is ua (s), then, corresponding to the axial force, the axial strain is: εa (s) = dua (s) Fτe = , ds EA therefore, the tubular string displacement is: l ua (s) = 0 Fτe ds. 30) ds0 . 2 ds0 Let ds0 be the arc infinitesimal of the well-bore axis, ds be the arc infinitesimal length for the normal plane of the two endpoints of ds0 cutting the tubular string, then corresponding to ds0 , the length ds0 without bending is: ds0 = (1 + rk0 )ds0 .